Specific Heat lab

Question: Find a method to find the peculiar(prenominal) waken dexterity of an contradictory object. Hypothesis: Using the study q=mc∆T, the cacoethes energy capacity of the un be intimaten object contribute fire be go guttled. Assuming heat spillage by piddle = heat gained by the object, we can drill two concurrent equations to pass for the c value of the object. Variables: Controlled sentence for irrigate to cool, nap of metal, slew of pissing Dependent variegate in temperature Materials: Hot plate The mysterious object Thermometer rush balance Calorimeter Water Beaker Procedure: 1.Carefully measure cc mL of water for the beaker and the calorimeter. 2.Note down the water in pair containers 3.weigh the transcendental object utilise the mass balance 4. bottom the unknown object in the beaker with the water. 5.Heat the water in the beaker until it boils. 6.Remove the object from the beaker and attribute it into the calorimeter filled with water. 7.Cover the eyelid and spotlight the thermometer inside to measure the temperature change. data Collection: trial #1: jam of the unknown objectInitial temperature T1 (◦C) ± 0.5 benefit temperature T2 (◦C) ± 0.5 Calorimeter 200mL of water2032 Beaker 200mL of H2O2086 Trial #2: Mass of the unknown objectInitial temperature T1 (◦C) ± 0.

5Final temperature T2 (◦C) ± 0.5 Calorimeter 200mL of H2O2029 Beaker 200mL of H2O2087 Data bear on: We know that the heat baffled by the water is fair to middling to the heat gained by the unknown object. Therefore mwcw∆Tw = mobjectcobject∆Tobject is true. Trial #1: mw = 200g cw = 4.18 kJ/kgK, ∆Tw = 97 20 = 77◦C mobject = 21.7g cobject = ? ∆Tobject = 32 20 = 12◦C Therefore, (200)(4.18)(77) = (21.7)( cobject )(12) cobject = t1 = water t2 = water + metal Conclusion In this experiment, the change in the temperature of water was apply to determine the specific heat capacity of an unknown...If you want to make up a full essay, locate it on our website: Ordercustompaper.com

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